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Year 11 Methods (Unit 1 & 2) Probability

Estimating Probabilities

20 practice questions 1 video lesson Theory + worked examples

Learn to estimate probabilities from data for Queensland Year 11 Mathematical Methods (QCAA). When outcomes are not equally likely, the relative frequency of an event over many trials estimates its probability.

You will learn to read frequency tables, treat relative frequencies as point estimates of probabilities, compute an expected number as probability times trials, and watch estimates settle as trials increase — groundwork for conditional probability and independence.

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Theory

In Year 11 Mathematical Methods (QCAA, Unit 1 Topic 5), an experimental probability is estimated from data using the relative frequency \(\dfrac{\text{frequency}}{\text{total trials}}\). This page shows how to estimate a probability from a table or bar chart, predict the expected number of occurrences, and compare experimental with theoretical probability.

The relative frequency of an outcome is how often it happened divided by the number of trials: \(\dfrac{\text{frequency}}{\text{total trials}}\). We use it as an experimental (estimated) probability when the true probability is unknown or the outcomes are not equally likely.

The expected number of times an outcome occurs in \(n\) trials is the estimated probability multiplied by \(n\). It is a prediction of a count, so we usually round to a whole number.

By the law of large numbers (used informally here), the relative frequency settles closer to the true probability as the number of trials grows — a larger sample gives a more reliable estimate.

Estimate from data, calculate from theory. Experimental probability comes from an experiment; theoretical probability comes from equally likely outcomes. They are usually close but rarely identical.
Results of tossing a drawing pin two hundred timesA bar chart: point-up occurred 130 times and point-down 70 times out of 200 tosses. 130 up 70 down
From \(200\) tosses a drawing pin landed point-up \(130\) times, so the relative frequency is \(\dfrac{130}{200}=0.65\).
Results of 100 spins of a coloured spinner
ColourRedBlueGreenTotal
Frequency453025100
A frequency table gives estimates directly: \(P(\text{red})\approx\dfrac{45}{100}=0.45\). The frequencies add to the total number of spins.

The experimental probability (relative frequency):

\[P(\text{event})\approx\dfrac{\text{frequency of event}}{\text{total number of trials}}\]
Pfrequencytrials

The expected number of occurrences in \(n\) trials:

\[\text{expected number}=P(\text{event})\times n\]
expected=P×n
Sanity check: the relative frequencies of all outcomes add to \(1\), and each lies in \([0,1]\). More trials give a more trustworthy estimate.

How to estimate and use a probability from data

  1. Read the frequency of the outcome and the total number of trials.
  2. Divide: experimental probability \(=\dfrac{\text{frequency}}{\text{total}}\).
  3. Predict a count: expected number \(=\) probability \(\times\) number of trials.
  4. Compare or scale: line the estimate up against the theoretical value, or use the complement \(P(\text{not})=1-P\) to answer the question.
Example 1 — Relative frequency
A drawing pin is tossed \(200\) times and lands point-up \(130\) times. Estimate the probability that it lands point-up.
Solution

Relative frequency \(=\dfrac{\text{frequency}}{\text{total}}\):

\(P(\text{up})\)\(=\)\(\dfrac{130}{200}\)

Simplify to a decimal:

\(=\)\(\dfrac{13}{20}\)
\(=\)\(0.65\)

\(P(\text{up})\approx 0.65\).

Drawing-pin experimentBar chart of 200 pin tosses; point-up 130 and point-down 70. 130 up 70 down
Example 2 — Expected number of occurrences
A component is faulty with estimated probability \(0.04\). In a batch of \(1500\) components, how many are expected to be faulty?
Solution

Expected number \(=P\times n\):

\(\text{expected}\)\(=\)\(0.04\times 1500\)

Multiply:

\(=\)\(60\)

About \(60\) faulty components are expected.

Estimated probabilities for a single component
OutcomeFaultyNot faulty
Estimated probability\(0.04\)\(0.96\)
Example 3 — Experimental vs theoretical
A die is rolled \(60\) times and a ‘\(5\)’ appears \(14\) times. Compare the experimental probability of a ‘\(5\)’ with the theoretical probability.
Solution

Experimental probability from the data:

\(P_{\text{exp}}\)\(=\)\(\dfrac{14}{60}\)
\(=\)\(\dfrac{7}{30}\approx 0.23\)

Theoretical probability for a fair die:

\(P_{\text{theory}}\)\(=\)\(\dfrac{1}{6}\approx 0.17\)

The experimental value \(0.23\) is a little higher than the theoretical \(0.17\); with more rolls it would be expected to settle closer to \(\dfrac{1}{6}\).

\(P_{\text{exp}}=\dfrac{7}{30}\approx 0.23\), above \(P_{\text{theory}}=\dfrac{1}{6}\approx 0.17\).

Results of rolling a die 60 times
Score on the die123456
Frequency811910148
Example 4 — Estimate, complement and scale
A spinner is spun \(100\) times with the results shown. Estimate \(P(\text{red})\), find \(P(\text{not red})\), and predict the number of reds in \(400\) spins.
Solution

Estimate \(P(\text{red})\) from the table:

\(P(\text{red})\)\(=\)\(\dfrac{45}{100}\)
\(=\)\(0.45\)

Complement rule for ‘not red’:

\(P(\text{not red})\)\(=\)\(1-0.45\)
\(=\)\(0.55\)

Scale up to \(400\) spins:

\(\text{expected reds}\)\(=\)\(0.45\times 400\)
\(=\)\(180\)

\(P(\text{red})=0.45\), \(P(\text{not red})=0.55\), and about \(180\) reds in \(400\) spins.

Results of 100 spins of the spinner
ColourRedBlueGreenTotal
Frequency453025100

Common pitfalls

Dividing by the wrong total. Relative frequency divides by the number of trials, not by the number of possible outcomes.
Confusing experimental with theoretical. Data give an estimate; equally likely outcomes give the exact theoretical value. Expect them to be close, not identical.
Treating the expected number as guaranteed. ‘\(60\) faulty’ is a prediction of the average, not a promise that exactly \(60\) will fail.
Ignoring sample size. An estimate from \(10\) trials is far less reliable than one from \(1000\); more trials tighten the estimate.

Frequently asked questions

What is relative frequency?

How often an outcome occurred divided by the number of trials: \(\dfrac{\text{frequency}}{\text{total}}\). It is used as an experimental probability.

What is the difference between experimental and theoretical probability?

Experimental probability is estimated from data (relative frequency); theoretical probability is calculated from equally likely outcomes.

How do you find the expected number of occurrences?

Multiply the estimated probability by the number of trials: expected number \(=P\times n\).

Why does more data give a better estimate?

By the law of large numbers the relative frequency settles closer to the true probability as the number of trials increases.

Can experimental probability equal theoretical probability?

It can, but usually they differ slightly. They tend to agree more closely as the number of trials grows.

Do relative frequencies have to add to 1?

Yes — across all outcomes the relative frequencies (like all probabilities) add to \(1\).