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Year 11 Methods (Unit 1 & 2) Exponential Functions And Logarithms

Rational Indices

20 practice questions 1 video lesson Theory + worked examples

Understand rational indices for Queensland Year 11 Mathematical Methods (QCAA). A fractional power is just another way of writing a root: a power of one over n means the nth root, linking index notation to surds.

You will learn to read a fractional index as a root, evaluate these powers, handle negative rational indices, and convert between surd form and index form — extending the index laws to every rational power.

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Theory

In Year 11 Mathematical Methods (QCAA, Unit 2), a rational (fractional) index means a root: \(a^{1/n}\) is the \(n\)th root of \(a\), and \(a^{m/n}\) raises that root to the power \(m\). This page shows how to evaluate fractional and negative rational indices and how to convert between surd (radical) and index form.

A rational index is an index that is a fraction. The denominator gives a root and the numerator gives a power: \(a^{1/n}=\sqrt[n]{a}\) is the number that, raised to the power \(n\), gives \(a\).

More generally \(a^{m/n}=\left(\sqrt[n]{a}\right)^{m}=\sqrt[n]{a^{m}}\). Taking the root first usually keeps the numbers small. A negative rational index combines this with the reciprocal rule, \(a^{-m/n}=\dfrac{1}{a^{m/n}}\). All the ordinary index laws still apply.

Denominator is the root, numerator is the power. For \(27^{2/3}\), cube-root first (\(\sqrt[3]{27}=3\)), then square (\(3^{2}=9\)).
A fractional index is a root and a power a to the m over n equals the nth root of a, all raised to the power m. The denominator is the root and the numerator is the power. a m n = (ⁿ√a)ᵐ numerator = power denominator = root
A fractional index \(a^{m/n}\): the denominator is the root, the numerator is the power.
Rational indices placed on a number line On a number line, four to the zero is one, four to the one half is two, and four to the one is four. 1 2 4 4⁰ 4½ is the square root of 4, which is 2
Fractional indices are ordinary numbers: \(4^{1/2}=\sqrt{4}=2\) sits between \(4^{0}\) and \(4^{1}\).

For a positive base \(a\) and positive integers \(m,\,n\):

\[a^{1/n}=\sqrt[n]{a}\qquad a^{m/n}=\left(\sqrt[n]{a}\right)^{m}=\sqrt[n]{a^{m}}\]
a1/n=an
\[a^{-m/n}=\dfrac{1}{a^{m/n}}\]
a-m/n=1am/n
Surd to index form: \(\sqrt{x}=x^{1/2}\) and \(\sqrt[n]{x^{m}}=x^{m/n}\). Rewriting a surd as an index lets you use the index laws.

How to evaluate \(a^{m/n}\)

  1. Root first: take the \(n\)th root of the base (the denominator tells you which root), so \(\sqrt[n]{a}\).
  2. Then the power: raise that result to the power \(m\) (the numerator).
  3. Handle a negative index last: if the index is negative, take the reciprocal at the end, \(a^{-m/n}=\dfrac{1}{a^{m/n}}\).
Example 1 — A unit fraction index (a root)
Evaluate \(64^{1/3}\).
Solution

A \(\tfrac13\) index means the cube root:

\(64^{1/3}\)\(=\)\(\sqrt[3]{64}\)

Find the number that cubes to \(64\):

\(=\)\(4\quad(\text{since }4^{3}=64)\)

\(64^{1/3}=4\).

641/3=4
Example 2 — A general fraction index
Evaluate \(27^{2/3}\).
Solution

Denominator \(3\) is the root, numerator \(2\) is the power — root first:

\(27^{2/3}\)\(=\)\(\left(\sqrt[3]{27}\right)^{2}\)
\(=\)\((3)^{2}\)

Now apply the power:

\(=\)\(9\)

\(27^{2/3}=9\).

272/3=9
Example 3 — A negative rational index
Evaluate \(16^{-3/4}\).
Solution

Negative index — take the reciprocal:

\(16^{-3/4}\)\(=\)\(\dfrac{1}{16^{3/4}}\)

Evaluate \(16^{3/4}\): fourth root, then cube:

\(16^{3/4}\)\(=\)\(\left(\sqrt[4]{16}\right)^{3}\)
\(=\)\((2)^{3}=8\)

Substitute back:

\(=\)\(\dfrac{1}{8}\)

\(16^{-3/4}=\dfrac{1}{8}\).

16-3/4=18
Example 4 — Surd form with the index laws
Simplify \(\sqrt[3]{x^{2}}\times \sqrt[3]{x}\), writing the answer in simplest form.
Solution

Convert each surd to index form:

\(\sqrt[3]{x^{2}}\)\(=\)\(x^{2/3}\)
\(\sqrt[3]{x}\)\(=\)\(x^{1/3}\)

Product law — add the indices:

\(x^{2/3}\times x^{1/3}\)\(=\)\(x^{\tfrac{2}{3}+\tfrac{1}{3}}\)
\(=\)\(x^{1}\)
\(=\)\(x\)

\(\sqrt[3]{x^{2}}\times \sqrt[3]{x}=x\).

x

Common pitfalls

Swapping root and power. In \(a^{m/n}\) the denominator \(n\) is the root and the numerator \(m\) is the power — not the other way around.
Multiplying the base by the index. \(64^{1/3}\) is the cube root of \(64\) (which is \(4\)), not \(64\div 3\).
Making a negative index give a negative answer. \(16^{-3/4}=\dfrac{1}{8}\), a positive fraction; the minus sign signals a reciprocal, not a negative value.

Frequently asked questions

What does a fractional index mean?

A fractional index is a root: \(a^{1/n}=\sqrt[n]{a}\). More generally \(a^{m/n}=\left(\sqrt[n]{a}\right)^{m}\), where the denominator is the root and the numerator is the power.

How do you evaluate a^(m/n)?

Take the \(n\)th root of the base first, then raise the result to the power \(m\). For \(27^{2/3}\), \(\sqrt[3]{27}=3\) then \(3^{2}=9\).

What does a negative fractional index give?

Take the reciprocal of the positive-index value: \(a^{-m/n}=\dfrac{1}{a^{m/n}}\). For example \(16^{-3/4}=\dfrac{1}{8}\).

How do you convert a surd to index form?

Write the root as the denominator of the index: \(\sqrt{x}=x^{1/2}\) and \(\sqrt[n]{x^{m}}=x^{m/n}\).

Why take the root before the power?

Rooting first keeps the numbers small, so \(27^{2/3}=(\sqrt[3]{27})^{2}=3^{2}=9\) is easier than cubing \(27\) first.