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Year 12 Methods (Unit 3 & 4) Trigonometry using the sine and cosine rules

Angles of elevation, angles of depression and bearings

20 practice questions 0 video lessons Theory + worked examples

In Year 12 Mathematical Methods (Queensland, QCAA), an angle of elevation is measured upwards from the horizontal and an angle of depression downwards from the horizontal; the two are equal by alternate angles. A bearing is a direction measured from north, clockwise — a three-figure true bearing such as \(035^\circ\text{T}\). These directions set up triangles you solve with right-angled trigonometry, the sine rule or the cosine rule.

The angle of elevation of an object is the angle between the horizontal and the line of sight when you look up at something higher than you. The angle of depression is the angle between the horizontal and the line of sight when you look down at something lower. Both are always measured from the horizontal, not from the vertical.

Because the horizontal line at the observer is parallel to the horizontal line at the object, the angle of depression from the observer equals the angle of elevation from the object back up to the observer — they are alternate angles between parallel lines. This equal-angle fact is the key to nearly every depression problem.

A bearing gives direction. A three-figure (true) bearing is measured from north, turning clockwise, and is written with three digits and a \(\text{T}\): due east is \(090^\circ\text{T}\), south \(180^\circ\text{T}\), west \(270^\circ\text{T}\). A compass bearing instead names the acute angle from north or south towards east or west, e.g. \(\text{S}\,50^\circ\text{E}\) (the same direction as \(130^\circ\text{T}\)). The back-bearing is the reverse direction, found by adding or subtracting \(180^\circ\).

Key idea. Elevation and depression are measured from the horizontal and are equal (alternate angles). Bearings run from north, clockwise. Draw the diagram, mark every angle, then choose right-angled trig, the sine rule, or the cosine rule.
Angle of elevation and angle of depression are equal (alternate angles)An observer at the top of a cliff looks down to a boat at angle of depression theta. The boat looks up to the observer at the equal angle of elevation theta, because the two horizontal lines are parallel. \(\theta\) \(\theta\) observer boat horizontal horizontal
Angle of depression \(\theta\) at the top equals the angle of elevation \(\theta\) at the boat
A three-figure bearing measured clockwise from northA compass centred at O with north, east, south and west. A direction to point P is measured clockwise from north through an angle of 125 degrees, giving the true bearing 125 degrees T. N E S W P 125° O
Bearing of \(P\) from \(O\): turn clockwise from north to get \(125^\circ\text{T}\)

Right-angled trigonometry (SOH–CAH–TOA) handles a single elevation or depression:

\[\sin\theta=\frac{\text{opp}}{\text{hyp}}\qquad \cos\theta=\frac{\text{adj}}{\text{hyp}}\qquad \tan\theta=\frac{\text{opp}}{\text{adj}}\]
tanθ=oppadj

When the triangle is not right-angled, use the sine rule (a side and its opposite angle) or the cosine rule (two sides and the included angle):

\[\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\qquad\qquad c^{2}=a^{2}+b^{2}-2ab\cos C\]
c2=a2+b2-2abcosC

Back-bearing (the reverse direction), kept between \(000^\circ\) and \(360^\circ\):

\[\text{back-bearing}=\begin{cases}\beta+180^\circ,&\beta<180^\circ\\[2pt]\beta-180^\circ,&\beta\ge 180^\circ\end{cases}\]
Choosing a tool. Right angle in the triangle → SOH–CAH–TOA. Two sides and the angle between → cosine rule. A side with its opposite angle plus one more fact → sine rule.

How to solve an elevation, depression or bearings problem

  1. Draw a clear diagram. Put in a north arrow at each relevant point; mark angles of elevation/depression from the horizontal and bearings clockwise from north.
  2. Transfer the directions to interior angles. Use alternate angles (depression = elevation), co-interior angles on parallel north lines, and back-bearings (\(\pm 180^\circ\)) to find the angles inside the triangle.
  3. Pick the right tool. A right angle → SOH–CAH–TOA. Two sides and the included angle → cosine rule. A complete opposite pair → sine rule.
  4. Substitute and solve. Keep full accuracy in the working; take the inverse trig function when finding an angle.
  5. Answer in context. Give a length to the stated precision and a bearing as a three-figure value \(\big(000^\circ\text{ to }360^\circ\big)\), or convert to compass form if asked.
Rounding. Work to at least four figures inside the calculation and round only the final answer; give bearings to the nearest degree unless told otherwise.
Example 1 — angle of elevation
From a point \(40\) m from the base of a tower on level ground, the angle of elevation to the top is \(32^\circ\). Find the height of the tower, correct to one decimal place.
Solution

Right-angled triangle; opposite \(=h\), adjacent \(=40\), so use \(\tan\).

\(\tan 32^\circ\)\(=\)\(\dfrac{h}{40}\)
\(h\)\(=\)\(40\tan 32^\circ\)
\(=\)\(25.0\ \text{m}\)
h=25.0
Example 2 — angle of depression
From the top of a \(60\) m cliff the angle of depression to a boat at sea is \(12^\circ\). Find the horizontal distance from the boat to the base of the cliff, to the nearest metre.
Solution

The elevation from the boat equals the depression, \(12^\circ\) (alternate angles). Height \(=60\), distance \(=d\).

\(\tan 12^\circ\)\(=\)\(\dfrac{60}{d}\)
\(d\)\(=\)\(\dfrac{60}{\tan 12^\circ}\)
\(=\)\(282\ \text{m}\)
d=282
Example 3 — back-bearing
The bearing of \(B\) from \(A\) is \(072^\circ\text{T}\). Find the bearing of \(A\) from \(B\).
Solution

Reverse the direction; since \(072^\circ<180^\circ\), add \(180^\circ\).

\(\text{bearing of }A\text{ from }B\)\(=\)\(072^\circ+180^\circ\)
\(=\)\(252^\circ\text{T}\)
072+180=252
Example 4 — bearings with the cosine rule
A ship sails \(5\) km from \(A\) on a bearing of \(030^\circ\text{T}\) to \(B\), then \(8\) km on a bearing of \(150^\circ\text{T}\) to \(C\). Find \(AC\).
Solution

At \(B\), the reverse of \(AB\) is \(210^\circ\), so \(\angle ABC=210^\circ-150^\circ=60^\circ\) (included angle).

\(AC^{2}\)\(=\)\(5^{2}+8^{2}-2(5)(8)\cos 60^\circ\)
\(=\)\(89-40=49\)
\(AC\)\(=\)\(7\ \text{km}\)
Bearings triangle for the ship sailing A to B to CPoint A at lower left, the ship sails up-right to B on 030 degrees, then down-right to C on 150 degrees. The interior angle at B is 60 degrees. AC is the third side. A B C N 5 km 8 km AC 60°
AC=7

Common pitfalls

Measure from the horizontal. Angles of elevation and depression are taken from the horizontal, not the vertical. Reading the angle from a vertical wall is the most common set-up error.
Depression equals elevation. The angle of depression from the top equals the angle of elevation from the bottom (alternate angles between parallel horizontals) — put the angle inside the triangle before using trig.
Bearings run clockwise from north with three digits. Write \(035^\circ\text{T}\), not \(35^\circ\); a back-bearing is \(\pm 180^\circ\), keeping the result between \(000^\circ\) and \(360^\circ\).

Frequently asked questions

What is an angle of elevation?

The angle measured upwards from the horizontal to your line of sight when you look up at an object higher than you.

What is an angle of depression?

The angle measured downwards from the horizontal to an object below you. It equals the angle of elevation from that object back up to you, because the two horizontals are parallel (alternate angles).

How is a three-figure bearing measured?

From north, turning clockwise, written with three digits and a T: \(035^\circ\text{T}\), \(210^\circ\text{T}\). East is \(090^\circ\), south \(180^\circ\), west \(270^\circ\).

How do you find a back-bearing?

Add \(180^\circ\) if the bearing is under \(180^\circ\), otherwise subtract \(180^\circ\), so the answer stays between \(000^\circ\) and \(360^\circ\). E.g. the reverse of \(072^\circ\) is \(252^\circ\).

When do you use the sine or cosine rule?

After marking the interior angles from the bearings: right-angled trig if there is a right angle, the cosine rule for two sides and the included angle, the sine rule for a side and its opposite angle plus one more fact.

What is the difference between a true and a compass bearing?

A true bearing is one clockwise angle from north (\(130^\circ\text{T}\)); a compass bearing names the acute angle from north or south towards east or west (\(\text{S}\,50^\circ\text{E}\) is the same direction).

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