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Year 11 Methods (Unit 1 & 2) Quadratics

The Discriminant

20 practice questions 1 video lesson Theory + worked examples

Understand the discriminant for Queensland Year 11 Mathematical Methods (QCAA). The discriminant is the part of the quadratic formula under the square root, and its sign counts the solutions.

You will learn to compute it, decide whether a quadratic has two, one or no real solutions, test whether those solutions are rational or irrational, and find an unknown coefficient for one repeated solution — all linked to the parabola's x-intercepts.

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Theory

In Year 11 Mathematical Methods (QCAA, Unit 1), the discriminant \(\Delta=b^2-4ac\) tells you how many solutions the quadratic \(ax^2+bx+c=0\) has — without solving it. This page shows how to compute \(\Delta\), read off the number and nature of the solutions, find an unknown coefficient for a stated condition, and link \(\Delta\) to the number of x-intercepts of the parabola.

The discriminant of \(ax^2+bx+c=0\) is the expression under the root sign in the quadratic formula, \(\Delta=b^2-4ac\). Its sign decides how many real solutions the equation has.

When \(\Delta>0\) there are two distinct real solutions; when \(\Delta=0\) there is one (a repeated, or equal, solution); when \(\Delta<0\) there are no real solutions.

When \(\Delta>0\) the nature can be refined: if \(\Delta\) is a perfect square the two solutions are rational (the quadratic factorises over the integers); otherwise they are irrational surds.

Sign of \(\Delta\) = number of solutions = number of x-intercepts. Two if \(\Delta>0\), one if \(\Delta=0\), none if \(\Delta<0\).
Discriminant positive means two x-interceptsParabola cutting the x-axis at two points; the discriminant is greater than zero. x y
\(\Delta>0\): the parabola cuts the \(x\)-axis at two points.
Discriminant zero touches, negative missesOne parabola touches the x-axis once when the discriminant is zero; a higher parabola misses it when the discriminant is negative. x y one none
\(\Delta=0\): the lower parabola just touches once; \(\Delta<0\): the upper one misses entirely.

For \(ax^2+bx+c=0\), the discriminant is:

\[\Delta=b^2-4ac\]
Δ=b2-4ac

The sign of \(\Delta\) gives the number of real solutions:

\[\Delta>0\ \Rightarrow\ 2,\qquad \Delta=0\ \Rightarrow\ 1,\qquad \Delta<0\ \Rightarrow\ 0\]
Δ>02,Δ=01,Δ<00
Equal roots condition: a quadratic has exactly one (repeated) solution — and its graph touches the \(x\)-axis — precisely when \(\Delta=b^2-4ac=0\).

How to use the discriminant

  1. Standardise: write the equation as \(ax^2+bx+c=0\) and read off \(a\), \(b\), \(c\) with their signs.
  2. Compute: evaluate \(\Delta=b^2-4ac\).
  3. Interpret: use the sign of \(\Delta\) for the number of solutions (and a perfect-square test for rational versus irrational), or set the required inequality/equation in \(\Delta\) to find an unknown coefficient.
Example 1 — Number and nature
For \(2x^2+3x-5=0\), find the discriminant and state the number and nature of the solutions.
Solution

Coefficients:

\(a\)\(=\)\(2\)
\(b\)\(=\)\(3\)
\(c\)\(=\)\(-5\)

Compute \(\Delta=b^2-4ac\):

\(\Delta\)\(=\)\((3)^2-4(2)(-5)\)
\(=\)\(9+40\)
\(=\)\(49\)

\(\Delta=49>0\), and \(49=7^2\) is a perfect square.

Two real solutions; since \(\Delta\) is a perfect square, they are rational.

Discriminant of 2x squared plus 3x minus 5Parabola with two rational x-intercepts. x y
Δ=49
Example 2 — Irrational solutions
How many solutions does \(x^2+4x+2=0\) have, and are they rational or irrational?
Solution

Coefficients:

\(a\)\(=\)\(1\)
\(b\)\(=\)\(4\)
\(c\)\(=\)\(2\)

Compute the discriminant:

\(\Delta\)\(=\)\((4)^2-4(1)(2)\)
\(=\)\(16-8\)
\(=\)\(8\)

\(\Delta=8>0\), but \(8\) is not a perfect square.

Two real solutions, and they are irrational (surds).

Discriminant of x squared plus 4x plus 2Parabola with two irrational x-intercepts. x y
Δ=8
Example 3 — Equal roots (find k)
Find the values of \(k\) for which \(x^2+kx+9=0\) has exactly one solution.
Solution

One solution means equal roots, so set \(\Delta=0\):

\(a\)\(=\)\(1\)
\(b\)\(=\)\(k\)
\(c\)\(=\)\(9\)

Form \(\Delta=b^2-4ac\) and equate to \(0\):

\(k^2-4(1)(9)\)\(=\)\(0\)
\(k^2-36\)\(=\)\(0\)
\(k^2\)\(=\)\(36\)
\(k\)\(=\)\(\pm 6\)

One solution when \(k=6\) or \(k=-6\).

Equal roots when k equals 6Parabola touching the x-axis once, at its turning point. x y
k=±6
Example 4 — No solutions (find c)
For what values of \(c\) does \(2x^2+4x+c=0\) have no real solutions?
Solution

No real solutions means \(\Delta<0\):

\(a\)\(=\)\(2\)
\(b\)\(=\)\(4\)
\(c\)\(=\)\(c\)

Form \(\Delta\) and require it to be negative:

\((4)^2-4(2)(c)\)\(<\)\(0\)
\(16-8c\)\(<\)\(0\)
\(16\)\(<\)\(8c\)
\(2\)\(<\)\(c\)

No real solutions when \(c>2\); the parabola then sits entirely above the \(x\)-axis.

No solutions when c is greater than 2Parabola sitting entirely above the x-axis, so there are no real solutions. x y
c>2

Common pitfalls

Sign slips in \(b^2-4ac\). Square \(b\) as a whole, so \((-4)^2=16\), and watch the sign of \(c\): with \(c=-5\), \(-4ac=+40\), not \(-40\).
Confusing number with nature. \(\Delta>0\) always gives two solutions; the perfect-square test only decides whether those two are rational or irrational.
Actually solving the equation. The discriminant answers how many and what kind — you do not need the root values, so do not run the whole quadratic formula.
Wrong condition for the task. Equal roots use \(\Delta=0\), two solutions use \(\Delta>0\), and none use \(\Delta<0\) — match the inequality to the words.

Frequently asked questions

What is the discriminant of a quadratic?

For \(ax^2+bx+c=0\) it is \(\Delta=b^2-4ac\); its sign tells you how many real solutions the equation has.

How does the discriminant tell the number of solutions?

\(\Delta>0\) gives two distinct real solutions, \(\Delta=0\) gives one repeated solution, and \(\Delta<0\) gives no real solutions.

How do I tell if the solutions are rational or irrational?

When \(\Delta>0\), check whether \(\Delta\) is a perfect square: if it is, the solutions are rational; if not, they are irrational surds.

What does the discriminant say about the graph?

It gives the number of \(x\)-intercepts of \(y=ax^2+bx+c\): two if \(\Delta>0\), one (a touch) if \(\Delta=0\), none if \(\Delta<0\).

How do I find a value that makes the roots equal?

Set \(\Delta=b^2-4ac=0\) and solve for the unknown coefficient; that is the equal-roots (tangency) condition.

Do I need to solve the equation to use the discriminant?

No — the discriminant is a shortcut that counts and classifies the solutions without finding them.