Simplifying Surds
Master simplifying surds for Queensland Year 11 Mathematical Methods (QCAA). A surd is an irrational root, and simplifying it means writing that root in its simplest exact form by pulling out perfect-square factors.
You will learn to break a root into factors, extract perfect squares to reach simplest form, recognise like surds, and add, subtract, multiply and divide surds confidently — building the exact-value skills used throughout algebra.
Theory
In Year 11 Mathematical Methods (QCAA, Unit 1), a surd is an irrational number written with a root sign, such as \(\sqrt{2}\) or \(\sqrt{5}\). Simplifying surds means writing a square root in its simplest exact form by extracting perfect-square factors, then adding, subtracting, multiplying and dividing surds. This page covers \(\sqrt{ab}=\sqrt{a}\,\sqrt{b}\), like surds, and surd arithmetic.
A surd is a square root of a natural number that is irrational — it cannot be written as an exact fraction or decimal. \(\sqrt{2},\ \sqrt{3}\) and \(\sqrt{5}\) are surds, but \(\sqrt{9}=3\) and \(\sqrt{16}=4\) are not, because \(9\) and \(16\) are perfect squares.
A surd is in simplest form when the number under the root has no perfect-square factor larger than \(1\). We simplify by finding the largest perfect-square factor and splitting the root with \(\sqrt{ab}=\sqrt{a}\,\sqrt{b}\).
Like surds have the same number under the root (for example \(3\sqrt{2}\) and \(5\sqrt{2}\)). Only like surds can be added or subtracted, by collecting their coefficients.
The product and quotient rules for surds (for \(a,b\ge 0\)):
Collecting like surds (same number under the root):
How to simplify a surd
- Factor: find the largest perfect-square factor of the number under the root (\(4,9,16,25,\dots\)).
- Split: use \(\sqrt{ab}=\sqrt{a}\,\sqrt{b}\) and take the exact root of the perfect square.
- Combine: for sums, collect like surds; for products, multiply coefficients and roots (\(p\sqrt{a}\times q\sqrt{b}=pq\sqrt{ab}\)), then re-simplify.
Largest perfect-square factor — \(72=36\times 2\):
| \(\sqrt{72}\) | \(=\) | \(\sqrt{36\times 2}\) |
Split the root and take \(\sqrt{36}\):
| \(=\) | \(\sqrt{36}\,\sqrt{2}\) | |
| \(=\) | \(6\sqrt{2}\) |
\(\sqrt{72}=6\sqrt{2}\).
Simplify each surd first:
| \(\sqrt{50}\) | \(=\) | \(\sqrt{25\times 2}=5\sqrt{2}\) |
| \(\sqrt{18}\) | \(=\) | \(\sqrt{9\times 2}=3\sqrt{2}\) |
| \(\sqrt{8}\) | \(=\) | \(\sqrt{4\times 2}=2\sqrt{2}\) |
They are all like surds — collect the coefficients:
| \(5\sqrt{2}-3\sqrt{2}+2\sqrt{2}\) | \(=\) | \((5-3+2)\sqrt{2}\) |
| \(=\) | \(4\sqrt{2}\) |
\(\sqrt{50}-\sqrt{18}+\sqrt{8}=4\sqrt{2}\).
Multiply coefficients, and the numbers under the roots:
| \(2\sqrt{6}\times 5\sqrt{3}\) | \(=\) | \((2\times 5)\sqrt{6\times 3}\) |
| \(=\) | \(10\sqrt{18}\) |
Simplify the surd — \(18=9\times 2\):
| \(10\sqrt{18}\) | \(=\) | \(10\sqrt{9}\,\sqrt{2}\) |
| \(=\) | \(10\times 3\sqrt{2}\) | |
| \(=\) | \(30\sqrt{2}\) |
\(2\sqrt{6}\times 5\sqrt{3}=30\sqrt{2}\).
Distribute \(\sqrt{5}\) over the bracket:
| \(\sqrt{5}\cdot 2\sqrt{5}\) | \(=\) | \(2\sqrt{25}=2\times 5=10\) |
| \(\sqrt{5}\cdot \sqrt{15}\) | \(=\) | \(\sqrt{75}=\sqrt{25\times 3}=5\sqrt{3}\) |
Combine the two terms:
| \(\sqrt{5}\,(2\sqrt{5}-\sqrt{15})\) | \(=\) | \(10-5\sqrt{3}\) |
\(\sqrt{5}\,\bigl(2\sqrt{5}-\sqrt{15}\bigr)=10-5\sqrt{3}\).
Common pitfalls
Frequently asked questions
What is a surd?
A surd is the square root of a natural number that is irrational, such as \(\sqrt{2}\) or \(\sqrt{7}\). Roots of perfect squares like \(\sqrt{9}=3\) are not surds.
How do you simplify a surd like \(\sqrt{72}\)?
Find the largest perfect-square factor: \(72=36\times 2\). Then \(\sqrt{72}=\sqrt{36}\,\sqrt{2}=6\sqrt{2}\).
When can you add or subtract surds?
Only when they are like surds — the same number under the root. Simplify each surd first, then collect coefficients, e.g. \(5\sqrt{2}+2\sqrt{2}=7\sqrt{2}\).
How do you multiply two surds?
Multiply the coefficients and multiply the numbers under the roots: \(p\sqrt{a}\times q\sqrt{b}=pq\sqrt{ab}\), then simplify the result.
Is \(\sqrt{a+b}\) the same as \(\sqrt{a}+\sqrt{b}\)?
No. The root does not split over a sum. For instance \(\sqrt{9+16}=\sqrt{25}=5\), but \(\sqrt{9}+\sqrt{16}=3+4=7\).