Mathematical induction
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To prove by mathematical induction that \(a + (a + d) + (a + 2d) + \cdots + (a + (n - 1)d) = \dfrac{n}{2}(2a + (n - 1)d)\) it is assumed that \(a + (a + d) + (a + 2d) + \cdots + (a + (k - 1)d) = \dfrac{k}{2}(2a + (k - 1)d)\). Then it must be proved that \(\dfrac{k}{2}(2a + (k - 1)d) + (a + kd) = \)
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