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Year 12 Maths Extension 2 Mechanics

Projectile Motion Without Resistance

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Question 1
30734

A particle is projected from \(O\) at an angle of \(\theta\) with a velocity of \(V\) metres per second. The particle lands at a distance of \(R\) metres from the origin at time \(T\). The equations of motion of the particle are \(\ddot{x} = 0\) and \(\ddot{y} = -g\).

Projectile from O at angle theta Velocity V at theta; dashed path following the launch angle; range R. x y O θ V R

(i) Using calculus, derive the expressions for the position of the particle at time \(t\).

(ii) Show that \(\tan\theta = \dfrac{gT^2}{2R}\).

(iii) Show that \(R = \dfrac{V^2\sin 2\theta}{g}\).

i) \(x = Vt\cos\theta\), \(y = Vt\sin\theta - \dfrac{1}{2}gt^2\)  ii) True  iii) True

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