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Year 11 Methods (Unit 1 & 2) Polynomials

Graphs Of Factorised Cubic Functions

20 practice questions 1 video lesson Theory + worked examples

Learn to sketch factorised cubic functions for Queensland Year 11 Mathematical Methods (QCAA). When a cubic is a product of linear factors, its graph follows from those factors.

You will learn to plot x-intercepts from the zeros, decide where the curve crosses or touches the x-axis from a repeated factor, mark the y-intercept, and read the behaviour for large positive and negative x from the sign of a.

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Theory

In Year 11 Mathematical Methods (QCAA, Unit 1), a factorised cubic \(y=a(x-x_1)(x-x_2)(x-x_3)\) can be sketched straight from its factors: the x-intercepts are the zeros, a squared factor makes the graph touch the axis while a single factor makes it cross, and the sign of \(a\) fixes the end behaviour. This page shows how to find the intercepts, read touch-versus-cross and sketch the cubic without calculus.

A factorised cubic is written \(y=a(x-x_1)(x-x_2)(x-x_3)\). The numbers \(x_1,x_2,x_3\) are the zeros, so the curve cuts the \(x\)-axis at \(x=x_1,\,x_2,\,x_3\). The y-intercept is found by putting \(x=0\).

The power of a factor is its multiplicity. A single (odd) factor makes the graph cross the axis; a squared (even) factor makes it just touch the axis and turn back. A cube factor \((x-h)^3\) flattens as it crosses.

The leading coefficient \(a\) sets the end behaviour. When \(a>0\) the cubic falls on the left and rises on the right; when \(a<0\) it does the opposite.

Read the graph from the factors: zeros give the \(x\)-intercepts, a squared factor means touch (not cross), and the sign of \(a\) tells you which way the ends point.
Cubic with three distinct x-interceptsA positive cubic that crosses the x-axis at three separate points and rises to the right. x y x1 x3
Three single factors: the cubic crosses at each of \(x_1,x_2,x_3\).
Cubic with a repeated factorA cubic that touches the x-axis at the squared factor and crosses at the single factor. x y touch cross
A squared factor gives a touch; the single factor still crosses.

For \(y=a(x-x_1)(x-x_2)(x-x_3)\):

\[y=0\ \Rightarrow\ x=x_1,\ x=x_2,\ x=x_3\]
x=x1,x2,x3
\[y\text{-intercept}=a(0-x_1)(0-x_2)(0-x_3)\]
y=a(-x1)(-x2)(-x3)
Multiplicity rule: an odd power \((x-h)\) or \((x-h)^3\) crosses the axis; an even power \((x-h)^2\) touches it. End behaviour: \(a>0\) rises to the right, \(a<0\) falls to the right.

How to sketch a factorised cubic

  1. Zeros: set each factor to \(0\) to get the \(x\)-intercepts.
  2. Multiplicity: mark each intercept as a cross (single or cube factor) or a touch (squared factor).
  3. y-intercept: substitute \(x=0\) into the factor form.
  4. Ends: use the sign of \(a\) — \(a>0\) rises to the right, \(a<0\) falls — then join the points into a smooth curve.
Example 1 — Three single factors
Find the intercepts of \(y=(x+2)(x-1)(x-3)\) and describe its end behaviour, then sketch it.
Solution

x-intercepts — set each factor to \(0\):

\((x+2)(x-1)(x-3)\)\(=\)\(0\)
\(x\)\(=\)\(-2,\ 1,\ 3\)

Each is a single factor, so the curve crosses at all three.

y-intercept — substitute \(x=0\):

\(y\)\(=\)\((0+2)(0-1)(0-3)\)
\(=\)\((2)(-1)(-3)\)
\(=\)\(6\)

End behaviour — the leading term is \(x^3\), so \(a=1>0\):

\(\text{left}\)\(\to\)\(-\infty\)
\(\text{right}\)\(\to\)\(+\infty\)

Intercepts \((-2,0),(1,0),(3,0)\) and \((0,6)\); rises to the right.

Graph of y equals (x+2)(x-1)(x-3)A positive cubic crossing the x-axis at minus 2, 1 and 3 with y-intercept 6. x y (0,6)
x=-2,1,3
Example 2 — A squared factor (touch)
Sketch \(y=-(x+1)(x-2)^2\), showing the intercepts and how the graph meets the axis.
Solution

x-intercepts:

\(-(x+1)(x-2)^2\)\(=\)\(0\)
\(x\)\(=\)\(-1\ \text{(single)},\ 2\ \text{(squared)}\)

At \(x=-1\) the graph crosses; at \(x=2\) it touches and turns back.

y-intercept — put \(x=0\):

\(y\)\(=\)\(-(0+1)(0-2)^2\)
\(=\)\(-(1)(4)\)
\(=\)\(-4\)

End behaviour — leading term \(-x^3\), so \(a=-1<0\):

\(\text{left}\)\(\to\)\(+\infty\)
\(\text{right}\)\(\to\)\(-\infty\)

Crosses at \((-1,0)\), touches at \((2,0)\), \(y\)-intercept \(-4\); falls to the right.

Graph of y equals minus (x+1)(x-2) squaredA negative cubic crossing at minus 1 and touching the x-axis at 2 with y-intercept minus 4. x y cross touch
x=-1,2
Example 3 — A factor of \(x\)
Sketch \(y=2x(x+2)(x-3)\), stating the intercepts and end behaviour.
Solution

x-intercepts — the factor \(x\) gives a zero at the origin:

\(2x(x+2)(x-3)\)\(=\)\(0\)
\(x\)\(=\)\(-2,\ 0,\ 3\)

All three factors are single, so the curve crosses at each.

y-intercept — substitute \(x=0\):

\(y\)\(=\)\(2(0)(0+2)(0-3)\)
\(=\)\(0\)

The curve passes through the origin \((0,0)\).

End behaviour — leading term \(2x^3\), so \(a=2>0\):

\(\text{left}\)\(\to\)\(-\infty\)
\(\text{right}\)\(\to\)\(+\infty\)

Intercepts \((-2,0),(0,0),(3,0)\); rises to the right.

Graph of y equals 2x(x+2)(x-3)A positive cubic through the origin crossing the x-axis at minus 2, 0 and 3. x y x1 x3
x=-2,0,3
Example 4 — Build the rule from a graph
A cubic crosses the \(x\)-axis at \(x=-3\), just touches it at \(x=1\), and passes through \((0,-3)\). Find its rule in factor form.
Solution

Factors — a cross is a single factor, a touch is a squared factor:

\(y\)\(=\)\(a(x+3)(x-1)^2\)

Find \(a\) — substitute the point \((0,-3)\):

\(-3\)\(=\)\(a(0+3)(0-1)^2\)
\(-3\)\(=\)\(a(3)(1)\)
\(-3\)\(=\)\(3a\)
\(a\)\(=\)\(-1\)

Write the rule with \(a=-1\):

\(y\)\(=\)\(-(x+3)(x-1)^2\)

Rule: \(y=-(x+3)(x-1)^2\).

Graph of y equals minus (x+3)(x-1) squaredA negative cubic crossing at minus 3 and touching the x-axis at 1 with y-intercept minus 3. x y cross touch
y=-(x+3)(x-1)2

Common pitfalls

Sign-flipping the zeros. The factor \((x+2)\) gives the zero \(x=-2\), not \(x=2\). Set each factor to \(0\) and solve.
Treating a squared factor as a crossing. \((x-2)^2\) makes the graph touch and turn back at \(x=2\); it does not pass through the axis there.
Ignoring the sign of \(a\). A negative leading coefficient flips the whole picture — the graph falls (not rises) on the right.
Forgetting the y-intercept. Substitute \(x=0\) into the factor form; do not read it as the constant of an expanded form you have not found.

Frequently asked questions

How do you find the x-intercepts of a factorised cubic?

Set each factor equal to \(0\) and solve. For \(y=a(x-x_1)(x-x_2)(x-x_3)\) the intercepts are \(x=x_1,x_2,x_3\).

What does a squared factor do to a cubic graph?

A squared factor \((x-h)^2\) makes the graph touch the \(x\)-axis at \(x=h\) and turn back, rather than crossing through it.

How do you find the y-intercept of a factorised cubic?

Substitute \(x=0\) into the factor form: \(y=a(0-x_1)(0-x_2)(0-x_3)\).

How does the sign of a change the graph?

If \(a>0\) the cubic rises to the right (and falls to the left); if \(a<0\) it falls to the right (and rises to the left).

Do I need calculus to sketch a factorised cubic?

No. In Year 11 you sketch from the intercepts, the multiplicity of each factor, the \(y\)-intercept and the sign of \(a\) — turning-point coordinates are not required.