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Year 11 Methods (Unit 1 & 2) Coordinate Geometry And Linear Relations

Families Of Straight Lines.

20 practice questions 1 video lesson Theory + worked examples

Exploring families of straight lines is a foundational skill assumed for Queensland Year 11 Mathematical Methods (QCAA). A family is a set of lines sharing a feature controlled by a parameter — a fixed gradient, or a common point they share.

You will recognise the shared feature, describe a parallel family or a fixed-point family, and find the single member that meets an extra condition — sharpening your feel for the gradient.

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Theory

In Year 11 Mathematical Methods (QCAA), a family of straight lines is a set of lines that share a feature controlled by a parameter. A parallel family \(y=mx+c\) fixes the gradient \(m\) and varies \(c\); a fixed-point family keeps a common point and varies the gradient. This page shows how to recognise the shared feature and find the member that meets an extra condition.

A family of lines is described by an equation with a parameter. As the parameter changes, each value gives one line (a member) of the family, and all members share one feature.

In a parallel family \(y=mx+c\) the gradient \(m\) is fixed and the intercept \(c\) varies, so every member is parallel. In a fixed-point family such as \(y=mx+c_0\) (fixed \(c_0\), varying \(m\)) every member passes through the common point \((0,c_0)\); changing \(m\) rotates the line about that point, while changing \(c\) translates it up or down.

Find the parameter from the extra condition. Substitute the given point (or feature) into the family equation and solve for the parameter to pick out the required member.
A parallel family y=2x+cThree lines with gradient 2 and different intercepts; changing c slides the line up or down. x y c=0 c=2 c=-2
A parallel family \(y=2x+c\): fixed gradient, varying \(c\) slides the line.
A fixed-point family y=mx+1Several lines through the common point 0, 1 with different gradients; rotating about the fixed point. x y (0,1)
A fixed-point family \(y=mx+1\): every member passes through \((0,1)\).

Two common families:

\[\text{parallel family:}\quad y=mx+c,\quad m\text{ fixed},\ c\text{ varies}\]
y=mx+c
\[\text{fixed-point family:}\quad y-y_0=m(x-x_0),\quad (x_0,y_0)\text{ fixed}\]
y-y0=m(x-x0)
Reading the fixed point: in \(y-y_0=m(x-x_0)\) every member passes through \((x_0,y_0)\), whatever the value of \(m\), because that point makes both sides \(0\).

How to work with a family of lines

  1. Identify the shared feature: a fixed gradient (parallel family) or a fixed point (a family through one point).
  2. Write the family with its parameter, e.g. \(y=mx+c\) or \(y-y_0=m(x-x_0)\).
  3. Apply the extra condition (a point, an intercept, or a gradient) and solve for the parameter to name the member.
Example 1 — A member of a parallel family
The family \(y=2x+c\) consists of all lines with gradient \(2\). Find the member that passes through \((1,\,4)\).
Solution

Substitute \((1,4)\) into \(y=2x+c\):

\(4\)\(=\)\(2(1)+c\)
\(4\)\(=\)\(2+c\)

Solve for the parameter \(c\):

\(c\)\(=\)\(4-2\)
\(c\)\(=\)\(2\)

Member: \(y=2x+2\).

Member of y=2x+c through (1,4)The parallel-family member y equals 2x plus 2 passing through 1, 4. x y (1,4) (0,2)
y=2x+2
Example 2 — A member of a fixed-point family
Every line \(y=mx+1\) passes through \((0,\,1)\). Find the member that also passes through \((3,\,7)\).
Solution

Substitute \((3,7)\) into \(y=mx+1\):

\(7\)\(=\)\(m(3)+1\)
\(7\)\(=\)\(3m+1\)

Solve for the parameter \(m\):

\(3m\)\(=\)\(6\)
\(m\)\(=\)\(2\)

Member: \(y=2x+1\).

Member of y=mx+1 through (3,7)The fixed-point-family member y equals 2x plus 1 through 3, 7 and the common point 0, 1. x y (3,7) (0,1)
y=2x+1
Example 3 — A member with a given intercept
In the family \(y=2x+c\), find the value of \(c\) for which the line has \(x\)-intercept \(3\).
Solution

At the \(x\)-intercept \(y=0\) and \(x=3\); substitute:

\(0\)\(=\)\(2(3)+c\)
\(0\)\(=\)\(6+c\)

Solve for \(c\):

\(c\)\(=\)\(-6\)

Member: \(c=-6\), i.e. \(y=2x-6\).

Member of y=2x+c with x-intercept 3The line y equals 2x minus 6 which crosses the x axis at 3, 0. x y (3,0) (0,-6)
c=-6
Example 4 — A pencil of lines through a fixed point
The family \(y=m(x+1)+2\) is a pencil of lines through a fixed point. State the fixed point, then find the member through \((1,\,8)\).
Solution

Fixed point — the value of \(x\) that removes \(m\) is \(x=-1\):

\(y\)\(=\)\(m(-1+1)+2\)
\(=\)\(m(0)+2\)
\(=\)\(2\)

So every member passes through the fixed point \((-1,\,2)\).

Substitute \((1,8)\) to find \(m\):

\(8\)\(=\)\(m(1+1)+2\)
\(8\)\(=\)\(2m+2\)
\(2m\)\(=\)\(6\)
\(m\)\(=\)\(3\)

Fixed point \((-1,\,2)\); member \(y=3x+5\).

Member of y=m(x+1)+2 through (1,8)The pencil member y equals 3x plus 5 through the fixed point negative 1, 2 and the point 1, 8. x y (1,8) (-1,2)
y=3x+5

Common pitfalls

Thinking every family is parallel. Only a fixed-gradient family \(y=mx+c\) is parallel. A family with a common point (varying \(m\)) is a rotating pencil, not parallel.
Confusing the roles of \(m\) and \(c\). Changing \(c\) translates a line up or down; changing \(m\) rotates it (changes steepness). Be clear which parameter varies.
Guessing the fixed point. Find it properly: the fixed point of \(y-y_0=m(x-x_0)\) is \((x_0,y_0)\), the value that makes the \(m\)-term vanish.

Frequently asked questions

What is a family of straight lines?

A set of lines described by an equation with a parameter; each parameter value gives one member, and all members share one feature such as a gradient or a common point.

What does changing c do in y = mx + c?

It translates the line vertically: the gradient stays the same, so the whole family is parallel, sliding up as \(c\) increases.

What does changing m do?

It changes the steepness, rotating the line about its \(y\)-intercept \((0,c)\). Members share that point but have different gradients.

How do you find the fixed point of a family?

Write it in the form \(y-y_0=m(x-x_0)\); the fixed point is \((x_0,y_0)\), because that point makes the \(m\)-term zero for every \(m\).

How do you find the member that passes through a given point?

Substitute the point into the family equation and solve for the parameter, then write out that particular line.