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Year 11 Methods (Unit 1 & 2) Applications Of Differentiation Of Polynomials

Types Of Stationary Points

20 practice questions 1 video lesson Theory + worked examples

Learn the types of stationary points for Queensland Year 11 Mathematical Methods (QCAA). Once a curve levels off, it may reach a local maximum, a local minimum, or a stationary point of inflection.

You will learn to determine the nature of each stationary point with the first-derivative sign test, build a sign chart of the gradient, and describe how a curve behaves around each one — essential for accurate curve sketching.

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Theory

In Year 11 Mathematical Methods (QCAA, Unit 2), the nature of a stationary point — whether it is a local maximum, a local minimum or a stationary point of inflection — is decided with the first-derivative sign test: check the sign of \(f'(x)\) just before and just after the point. This page shows the sign test in full for each type.

Once a stationary point is located by solving \(f'(x)=0\), its nature is how the curve behaves around it. There are three types: a local maximum (a peak), a local minimum (a trough), and a stationary point of inflection (the curve flattens then continues the same way).

The first-derivative sign test classifies the point by the sign of \(f'(x)\) on each side. If \(f'\) changes \(+\rightarrow-\) the point is a maximum; if it changes \(-\rightarrow+\) it is a minimum; if \(f'\) keeps the same sign on both sides (no change) it is a stationary point of inflection.

First-derivative sign test only. Pick a test value each side of the stationary \(x\), find the sign of \(f'\) there, and read off the nature from how the sign changes. No second derivative is used in Year 11.
A local minimumParabola turning upward at its minimum where the gradient changes from negative to positive. x y min
A local minimum: \(f'\) changes from negative to positive (\(-\rightarrow+\)).
A local maximum and a local minimumCubic with a maximum on the left where the gradient goes positive to negative, and a minimum on the right where it goes negative to positive. x y max min
A local maximum (\(+\rightarrow-\)) and a local minimum (\(-\rightarrow+\)) on one cubic.

Let \(x=a\) be a stationary point (\(f'(a)=0\)). Test a value just below and just above \(a\):

\[f'(a^-)>0,\ f'(a^+)<0\ \Rightarrow\ ext{local maximum}\]
f(a-)>0,f(a+)<0max
\[f'(a^-)<0,\ f'(a^+)>0\ \Rightarrow\ ext{local minimum}\]
f(a-)<0,f(a+)>0min
\[\text{no sign change}\ \Rightarrow\ \text{stationary inflection}\]
no sign changestationary inflection
Same sign both sides means inflection. \(f'(x)=0\) alone does not tell you the type — the sign change (or lack of one) does.

How to classify a stationary point by the sign test

  1. Locate: find \(f'(x)\) and solve \(f'(x)=0\) for the stationary \(x\)-value(s).
  2. Test each side: choose a value just below and just above each stationary \(x\), substitute into \(f'(x)\), and record the sign.
  3. Read the nature: \(+\rightarrow-\) is a maximum, \(-\rightarrow+\) is a minimum, and no change is a stationary point of inflection; then find the \(y\)-coordinate from \(f(x)\).
Example 1 — Classify a minimum
Find and classify the stationary point of \(y=x^2-4x+3\).
Solution

Locate — solve \(f'(x)=0\):

\(f'(x)\)\(=\)\(2x-4\)
\(2x-4\)\(=\)\(0\)
\(x\)\(=\)\(2\)

Sign test — test \(x=1\) and \(x=3\):

\(f'(1)\)\(=\)\(2(1)-4=-2<0\)
\(f'(3)\)\(=\)\(2(3)-4=2>0\)

The sign changes \(-\rightarrow+\), so \(x=2\) is a local minimum.

\(y\)-coordinate:

\(f(2)\)\(=\)\((2)^2-4(2)+3\)
\(=\)\(-1\)

Local minimum at \((2,\,-1)\).

Local minimum of a parabolaParabola with a local minimum at 2, minus 1 where the gradient changes from negative to positive. x y
min (2,-1)
Example 2 — A maximum and a minimum
Find and classify the stationary points of \(y=x^3-3x\).
Solution

Locate — solve \(f'(x)=0\):

\(f'(x)\)\(=\)\(3x^2-3\)
\(3x^2-3\)\(=\)\(0\)
\(3(x-1)(x+1)\)\(=\)\(0\)
\(x\)\(=\)\(-1 \ \text{or}\ 1\)

Sign test — test \(x=-2,\ 0,\ 2\):

\(f'(-2)\)\(=\)\(3(4)-3=9>0\)
\(f'(0)\)\(=\)\(-3<0\)
\(f'(2)\)\(=\)\(3(4)-3=9>0\)

At \(x=-1\): \(+\rightarrow-\), a local maximum. At \(x=1\): \(-\rightarrow+\), a local minimum.

\(y\)-coordinates:

\(f(-1)\)\(=\)\((-1)^3-3(-1)=2\)
\(f(1)\)\(=\)\((1)^3-3(1)=-2\)

Local maximum \((-1,\,2)\); local minimum \((1,\,-2)\).

Maximum and minimum of a cubicCubic with a maximum at minus 1, 2 and a minimum at 1, minus 2. x y
max (-1,2),min (1,-2)
Example 3 — A stationary point of inflection
Classify the stationary point of \(y=x^3-3x^2+3x+1\).
Solution

Locate — solve \(f'(x)=0\):

\(f'(x)\)\(=\)\(3x^2-6x+3\)
\(3(x-1)^2\)\(=\)\(0\)
\(x\)\(=\)\(1\)

Sign test — test \(x=\tfrac12\) and \(x=\tfrac32\):

\(f'\!\left(\tfrac12\right)\)\(=\)\(3\left(\tfrac12-1\right)^2=\tfrac34>0\)
\(f'\!\left(\tfrac32\right)\)\(=\)\(3\left(\tfrac32-1\right)^2=\tfrac34>0\)

The sign is \(+\) on both sides — no change — so this is a stationary point of inflection.

\(y\)-coordinate:

\(f(1)\)\(=\)\((1)^3-3(1)^2+3(1)+1\)
\(=\)\(2\)

Stationary point of inflection at \((1,\,2)\).

A stationary point of inflectionCubic that flattens at 1, 2 but keeps rising, a stationary point of inflection with no sign change. x y
inflection (1,2)
Example 4 — A quartic with two types
Find and classify the stationary points of \(y=x^4-4x^3\).
Solution

Locate — solve \(f'(x)=0\):

\(f'(x)\)\(=\)\(4x^3-12x^2\)
\(4x^2(x-3)\)\(=\)\(0\)
\(x\)\(=\)\(0 \ \text{or}\ 3\)

Sign test — test \(x=-1,\ 1,\ 4\):

\(f'(-1)\)\(=\)\(4(-1)(-4)=-16<0\)
\(f'(1)\)\(=\)\(4(1)(-2)=-8<0\)
\(f'(4)\)\(=\)\(4(16)(1)=64>0\)

At \(x=0\): \(-\rightarrow-\), no change, a stationary inflection. At \(x=3\): \(-\rightarrow+\), a local minimum.

\(y\)-coordinates:

\(f(0)\)\(=\)\(0\)
\(f(3)\)\(=\)\((3)^4-4(3)^3=81-108=-27\)

Stationary inflection \((0,\,0)\); local minimum \((3,\,-27)\).

Inflection and minimum of a quarticQuartic with a stationary point of inflection at the origin and a minimum at 3, minus 27. x y infl min
infl (0,0),min (3,-27)

Common pitfalls

Reaching for the second derivative. In Year 11 Methods the nature is decided by the first-derivative sign test only — test the sign of \(f'\) each side, never \(f''\).
Assuming a repeated root is a turning point. A double root of \(f'(x)=0\) (e.g. \(3(x-1)^2\)) usually gives no sign change — a stationary point of inflection, not a max or min. Always run the sign test.
Test values too far away. Choose test points close to the stationary \(x\) and between neighbouring stationary points, so the sign you read really belongs to that point.

Frequently asked questions

How do you tell if a stationary point is a maximum or minimum?

Use the first-derivative sign test: if \(f'\) changes from \(+\) to \(-\) it is a local maximum, and from \(-\) to \(+\) it is a local minimum.

What is a stationary point of inflection?

A stationary point where \(f'(x)=0\) but the sign of \(f'\) does not change — the curve flattens then keeps going the same way.

How do I run a first-derivative sign test?

Pick a value just below and just above the stationary \(x\), substitute each into \(f'(x)\), and note the signs; the pattern of change gives the nature.

Can I use the second derivative instead?

Not in Year 11 Methods — the syllabus classifies stationary points with the first-derivative sign test. The second-derivative test is Year 12.

Does f'(x)=0 tell me the type of point?

No. It only locates the stationary point. You still need the sign test to decide maximum, minimum or inflection.

What if the two test signs are the same?

No sign change means the point is a stationary point of inflection, not a maximum or a minimum.