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Year 11 General Shape And Measurement

Surface Area

20 practice questions 0 video lessons Theory + worked examples

Theory

Surface area is the total area of all the outside faces of a 3D solid. This page covers the surface area formulas for the cube, rectangular prism, cylinder, cone, sphere and hemisphere, with worked examples on painting costs and Pythagoras-based slant heights.

The surface area of a 3D solid is the total area of all of its outside faces, measured in square units (cm2, m2, etc.). One useful way to picture it: imagine peeling the surface off the solid and laying it flat — the surface area is the area of the resulting net.

For a prism or pyramid, surface area is the sum of the areas of each face. For curved solids like the cylinder, cone and sphere, there is a dedicated formula because the curved surface unrolls into a recognisable flat shape (a rectangle, a sector of a circle, and so on).

A hemisphere is half a sphere. Its surface area depends on whether you include the flat circular cut: the curved part alone is 2πr2, and including the flat base it becomes 3πr2. Always read the question carefully.

Net of a closed cylinder A closed cylinder unrolls into a flat net consisting of two circles of radius r and a rectangle of width 2 pi r and height h. πr² top circle h 2πr × h (curved side) 2πr πr² bottom circle Net = 2 circles + 1 rectangle
The net of a closed cylinder: two circles plus a rectangle.
Cone with radius, perpendicular height, and slant height A cone showing the base radius r, the perpendicular height h from base to apex, and the slant height s along the curved face. These are related by Pythagoras: s squared equals r squared plus h squared. h s r s² = r² + h²
A cone: the slant height s (not the perpendicular height h) is used in the surface area formula.

The standard surface area formulas:

Cube (side s) — six identical square faces:

SA=6s2
SA=6s2

Rectangular prism (length , width w, height h):

SA=2w+2h+2wh
SA=2w+2h+2wh

Closed cylinder (radius r, height h) — two circular ends plus the curved side:

SA=2πr2+2πrh
SA=2πr2+2πrh

Cone (radius r, slant height s) — base circle plus curved side:

SA=πr2+πrs
SA=πr2+πrs

Sphere (radius r):

SA=4πr2
SA=4πr2

Hemisphere. Curved part only: 2πr2. Curved part plus the flat circular base: 3πr2. Always check which version the question is asking for.

Cone with perpendicular height only. If the question gives the perpendicular height h instead of the slant s, find the slant first using Pythagoras: s=r2+h2.

How to find the surface area of any solid

  1. Identify each face of the solid. For a prism or pyramid, list the flat faces. For a cylinder, cone or sphere, recognise the standard shape and use its formula.
  2. Compute the area of each face using the matching formula (rectangle =w, triangle =12bh, circle =πr2, curved cylinder =2πrh, curved cone =πrs).
  3. Add all the face areas together, and write the answer in square units. If the solid is open, leave out the missing face(s).

Composite or unusual solids. Break the solid into recognisable pieces (e.g.\ a cylinder topped by a hemisphere), compute each piece's surface area, and add them — but subtract any face that is hidden where the pieces meet.

Example 1 — Rectangular Prism
A box is 8 cm long, 5 cm wide and 3 cm tall. Find its surface area.
Rectangular box 8 by 5 by 3 cm A rectangular prism with length 8 cm, width 5 cm, and height 3 cm. 8 cm 3 cm 5 cm
Solution

Use the rectangular-prism formula.

SA=2w+2h+2wh
SA=2(40)+2(24)+2(15)
SA=80+48+30
SA=158 cm2
SA=158
Example 2 — Closed Cylinder
A closed cylinder has radius 4 cm and height 10 cm. Find its surface area to two decimal places.
Closed cylinder with radius 4 cm and height 10 cm A vertical cylinder with radius 4 centimetres and height 10 centimetres. r = 4 cm h = 10 cm
Solution
SA=2πr2+2πrh
SA=2π(16)+2π(4)(10)
SA=32π+80π
SA=112π
SA351.86 cm2
SA351.86
Example 3 — Cone (find slant first)
A cone has base radius 6 cm and perpendicular height 8 cm. Find its surface area to two decimal places.
Cone with radius 6 cm and perpendicular height 8 cm A cone with base radius 6 centimetres and perpendicular height 8 centimetres. The slant height is found by Pythagoras. h = 8 s r = 6
Solution

Find the slant height by Pythagoras, then apply the cone formula.

s=62+82
s=100=10
SA=πr2+πrs
SA=36π+60π
SA=96π
SA301.59 cm2
SA301.59
Example 4 — Painting Cost
The four walls and the ceiling of a room (5 m × 4 m × 3 m) are to be painted. Paint covers 10 m2 per litre and costs $22 per litre, sold in whole litres only. Find the cost.
Room 5 m by 4 m by 3 m for painting A rectangular room with floor 5 metres long by 4 metres wide and height 3 metres. The four walls and ceiling are to be painted. 5 m 3 m 4 m walls + ceiling
Solution

Find the area to be painted, then convert to litres (rounding up).

walls=2(5)(3)+2(4)(3)
walls=30+24=54
ceiling=5×4=20
total=74 m2
litres=74÷10=7.48
cost=8×$22=$176
cost=176

Common pitfalls

Forgetting the 2π on the curved side of a cylinder. The curved face has dimensions circumference × height, which is 2πr×h, not r×h. Without the 2π the answer is way off.
Open vs closed cylinders. A "closed" cylinder has both ends. An "open" cylinder (a tube) has none. "Open at the top" (a paint can with no lid) has only one. Read the question word for word and add the right number of πr2 caps.
Perpendicular vs slant height on a cone. The cone surface area formula uses the slant height s. If only the perpendicular height h is given, find s using Pythagoras: s2=r2+h2.
Mixed units. Convert lengths to the same unit before substituting. Mixing cm and m will give answers off by a factor of 100 or 10000.

Frequently asked questions

What is surface area?

Surface area is the total area of all the outside faces of a 3D solid, measured in square units like square centimetres or square metres. If you peeled the surface off the solid and laid it flat, the surface area would be the area of the resulting net.

What is the surface area formula for a cylinder?

For a closed cylinder with radius r and height h, the surface area is 2 pi r squared plus 2 pi r h. The two pi r squared is the area of the two circular ends, and 2 pi r h is the area of the curved side (its circumference times its height).

What is the difference between a closed cylinder and an open cylinder?

A closed cylinder has both circular ends, so its surface area is 2 pi r squared plus 2 pi r h. An open cylinder (like a tube) has no ends, so the surface area is just 2 pi r h. A cylinder open at the top (like a paint can with no lid) has only one end, so the surface area is pi r squared plus 2 pi r h.

Why does the cone formula use the slant height instead of the perpendicular height?

The curved surface of a cone unrolls into a sector of a circle whose radius is the slant height s, not the perpendicular height h. If you are only given the perpendicular height and the radius, find the slant height first using Pythagoras: s squared equals r squared plus h squared.

What is the surface area of a hemisphere?

It depends whether the flat circular face is included. The curved part alone is 2 pi r squared. Including the flat base, the total is 3 pi r squared. Always read the question to see which one is being asked for.

How do I work out how much paint to buy for a wall?

First calculate the total area to be painted in square metres. Divide by the coverage rate of the paint (square metres per litre) to get the number of litres needed. Then round up to the next whole litre because paint is sold in whole tins, and multiply by the cost per litre.

Practice Questions

20 questions available.

Practice Questions